Speed Spool Free Interrelated Roadmap


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reels Speed Spool Free Interrelated Roadmap

As you devor this article, remember that the rest of it contains valuable information related to Speed Spool for your reading pleasure. This piece will provide you with not just general Speed Spool information but also specific and helpful information.


Physics question involving circular motion, please help!! and thanks in advance?
An audiocassette has an empty spool (B) of diameter 21mm while that of the full spool Speed Spool (A) is 51mm. The tape travels from spool A to spool B at a contant speed of 48 mm/s taking exactly 45 minutes to empty spool A. Calculate:1)the total length of the tape in the cassette2)the initial angular speeds of the two spools3) How will the motion of the two spools vary as the tape is being played?thank you soo much!!
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reels Speed Spool Free Interrelated Roadmap

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11 Responses to “Speed Spool Free Interrelated Roadmap”

  1. Matthew Hendrix Says:

    i think it would, but it wouldnt be that fast

  2. yittrium39 Says:

    a) Torque = Force * DistanceTorque = mg*RTorque = (4.70 * 9.81 * .06)For direction, look at the diagram (and remember the right hand rule)b) L = I*ww = v/RI = (1/2)(M)(R^2) + mR^2(here we are treating the block as a particle orbiting around the axis O)L = (M/2 + m)*R*VL = (2.4/2 + 4.7)*.06*Vc) Torque = dL/dtsince L = (I*V/R)T = (I*A/R)we have torque from part a)and we have I/R from part b)so (T*R/I) = AA = (answer from part a / answer from part b)

  3. (Φ)kaksi_guy Says:

    ♠ linear speed of the line v=w*r, where w=2.6*2pi rad/s, r=3.4 cm;v= 2.6*2pi * 3.4 = 55.54336 cm/s;♣ also tripled; what a ∫hιτ-hεαd this Tony is!

  4. Ernie Says:

    It should be the same linear velocity as the thread. So 2 times the 3/4.

  5. i always need help Says:

    about $3000-$5000 becuase its a rebuilt engine and

  6. Straight Talker Says:

    There is no inherent difference in speed just based on 64 or 32 bit processing. The speed differences lie in the Operating System, and how they process applications. Most 32 bit apps will run a bit faster on a native 32 bit system, simply because the OS doesn’t have to make allowances for the different word length. With today’s processors though, the difference will be minimal. What 64 bit processing brings to the table is a much larger addressable memory space, which is why big databases and the like have been run on 64 bit systems for quite a few years now. Basically, as long as you have a reasonably fast modern CPU, the differences wont be worth worrying about.

  7. knr Says:

    by conservation of energy P.E lost + K.E gainedie., m g h = 1/ 2 m r^2 w^2, where ‘w’ is the required angular velocitythen, w = square root of ( 2 g h ) / r = square root of ( 2 x9.8 x4) / 0.5 = 17.7 rad/sec.

  8. Physicsquest Says:

    mg of bucket = 3 x 9.8 = 29.4 NTorque created by bucket:Force x radius = torque = 29.4 x 0.6 = 17.64 NmThe pully is a disc, inertia for a disc = 1/2mr^2 = 0.5 x 5 x 0.6^2 = 0.9 kg-m^2torque also equals inertia x alpha (rad/s^2)17.64 = 0.9alpha17.64/0.9 = alpha = 19.6 rad/s^2circumference of pulley = 0.6 x 2pi = 3.77 m3.77/2pi = 0.6 (repeating myself i know, but just showing you how and why i get to 5.9167 radians)3.55 / 0.6 = 5.9167 radians5.9167/(0.5 x 19.6) = t^2 = 0.6037, sq-root = t = 0.777 secsomega = alpha x time = 19.6 x 0.777 = 15.23 rad/s

  9. Etienne de Quercy Says:

    apply the second Newton’s law

  10. zoomjet Says:

    If this is recent behaviour, try your printer diagnostics; also check ink levelsalso go to control panel>printers and faxes, right click your printer and have a look at properties>advancedcheck if your printer is set to print after the last page is spooled; set it to print immediately

  11. Erase Program Read Only Memory Says:

    Bleed air is taken from two bleed ports say the engine is CFM56B1 for B737-300, there is low stage bleed port on the 9th compressor stage and a high stage on the 14th stage compressor. during low speed or throttle lever at idle the engine bleed from the low stage is not enough to supply the users so high stage valve opens up the 14th stage to supply the aircraft user’s need. The high pressure will push the low stage (9th) valve to close. At cruise or high power setting the bleed coming from the low stage (9th) is enough to supply the aircraft users so the High stage valve will stay close the 14th stage bleed port.

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